Vedic Maths 2017 : Tricks for fast mental calculation.
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Vedic Maths 2017 : Tricks for fast mental calculation.

Advanced shortcuts to solve problems accurately with unexpected speed.
5.0 (1 rating)
Instead of using a simple lifetime average, Udemy calculates a course's star rating by considering a number of different factors such as the number of ratings, the age of ratings, and the likelihood of fraudulent ratings.
727 students enrolled
Created by Kamal Thakur
Last updated 7/2016
English
Curiosity Sale
Current price: $10 Original price: $20 Discount: 50% off
30-Day Money-Back Guarantee
Includes:
  • 1.5 hours on-demand video
  • 11 Supplemental Resources
  • Full lifetime access
  • Access on mobile and TV
  • Certificate of Completion
What Will I Learn?
  • Fast mental Calculation (15- 20 times)
  • Better aptitude.
  • NO more maths fear.
View Curriculum
Requirements
  • A notebook and Pen
  • willing to learn new tricks and amaze others
Description

USE COUPON CODE :

 "LEARNING "

India has produced many mathematicians whose discoveries have benefitted the world. One such mathematician was Swami Bharati Krishna Tirtha (1884 – 1960). As a student of the Vedas from 1911 – 1918, he stumbled upon few Sutras (aphorisms or word-formulae). After extensive research on these sutras, he reconstructed 16 Sutras and 13 Upa-sutras using which numerical calculations can be done in simpler and faster ways. In Vedic Mathematics, unlike the conventional methods, there are many ways to arrive at a solution for a problem. This gives us the liberty to choose the technique most convenient for us. This is the beauty of Vedic Mathematics; it can be understood easily by people of any region. It enhances the ability to approach and solve any mathematical problem. 

Vedic Mathematics is a blessing to everybody in this day and age when people's numerical skills are deteriorating as the use of calculators is increasingly commencing at a younger age. Vedic Mathematics' shorter, quicker and easy to remember techniques enable any student to do calculations faster than they would with conventional methods. Students of Vedic Mathematics dispel their fear of mathematics and gain a new-found confidence to work on any mathematical problem without apprehension. This made easy course aims to promote the traditional knowledge of Mathematics mastered by the mathematicians of ancient India.

COURSE OBJECTIVES / REWARDS

  • Eradicates the fear of Mathematics and instills confidence
  • Improves calculation speed and numerical skills
  • Sharpens the brain
  • Is an aid to crack scholarship and entrance exams
  • Facilitates a habit of analytical thinking and measured approach towards any problem
  • Provides an insight into ancient Indian mathematics
  • Is useful for everyone – students, professionals, teachers, parents, and the young and old
  •  you can implement these shortcuts in Advanced machine learning functions.


Who is the target audience?
  • Aspirants of various Competitive Entrance Exams like CAT, GRE, Banks etc.
  • Students with weak aptitude and logic skills.
  • One who think maths is most terrible thing in this world.
Students Who Viewed This Course Also Viewed
Curriculum For This Course
21 Lectures
01:31:04
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Introduction
1 Lecture 02:39

Introducing course of Vedic mathematics, I named it as Made easy, as it will definitely make your life easy.

  • you'll learn various shortcuts and high speed calculation techniques..
  • Also providing pdf of  Algebraic proof for every shortcut within their section.
  • Please read Lecture descriptions before starting any lecture, this will provide you clear Idea of what you'll going to learn.
  • Don't forget to practice exercise questions given at the end of each lecture. 

Feel free to ask any queries.


Preview 02:39
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One more than the one before. ( Ekadhikena Purvena )
3 Lectures 10:09

After learning this you will be able to find square of a number ending with 5 say 25, 35, 45 etc. You can even try to find square of a three digit number ending with 5 say 105, 115, 125 etc.
Say you want to find square of 85
Do the following:
· Multiply 5 by 5 and put 25 as your right part of the answer.
· Multiply 8 by the next higher digit i.e 9 and put 72 as your left part of the answer.
· Your answer is 7225
You can use this formula to find square of any number ending with 5.

"Ekadhikena" in Square of numbers ending in 5
03:04

This lecture will lead you to be able to find decimal results of fraction numbers ending in 9,  i.e. 1/19, 1/29,1/249,1/1549 etc.
Although You can find result up to all the decimal places ,Mostly you'll need result of fraction up to 3 decimal places.

In the conversion of such vulgar fractions into recurring decimals, "Ekadhika" process can be
effectively used both in division and multiplication.


"Ekadhikena" in Vulgar Fraction whose denominator ending in 9 by division method
04:09

This lecture will lead you to be able to find decimal results of fraction numbers ending in 9,  i.e. 1/19, 1/29,1/249,1/1549 etc.

This is an effective method as to solve such Vulgar fraction by multiplying numbers instead of dividing.

Although this method is fast and easy, but to have result up to 3 decimal places this method is very lengthy. 

"Ekadhikena" in Vulgar Fraction whose deno. ending in 9 by Multiplication method
02:56
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All from 9 and the last from 10. ( Nikhilam navatascaramam Dasatah )
3 Lectures 18:00

In this lecture you will learn 6 rules to Multiply any TWO numbers nearer to bases like 10, 100 ,1000, 10000 etc.

i.e. 13 X 12 , 104 X 102, 1275 X 1004, 998 X 1025.

Since deviation is obtained by Nikhilam sutra we call the method as Nikhilam multiplication.

PROCESS:

  1. Depending upon the numbers closer to power of 10, we select that power of 10 as our Base.
  2. 2. Apply the principle of Nikhilam i.e. subtract the numbers from Base – All the digits from 9 and last from 10.  (write besides those numbers). Those numbers are called deviations, which may be positive or negative.
  3. Multiply those Deviations. (write in 2nd compartment).
  4. Do Cross Addition of Numbers with Deviations. (write in 1st Compartment)
  5. 2nd compartment ALWAYS needs to have same number of digits as that of zeroes of the selected Base. If less then pre-append zeroes. If more, carry forward initial digits to 1st compartment




"Nikhilam" Multiplication Rules
04:01

In this Lecture, you'll learn how to multiply two large numbers in your brain, here, you'll apply the rules studied in 5th lecture and practice some examples.

Also you'll learn various possible cases for numbers and deviations.

Case (i) : Both the numbers are lower than the base.We have considered the example 7 x 8 , with base 10.

Case ( ii) : Both the numbers are higher than the base. The method and rules follow as they are. The only difference is the positive deviation. Instead of cross – subtract, we follow cross – add.

Case ( iii ): One number is more and the other is less than the base. In this situation one deviation is positive and the other is negative. So the product of deviations becomes negative. So the right hand side of the answer obtained will therefore have to be subtracted.




"Nikhilam" Multiplication Examples with various cases
08:05

In this lecture, you'll learn how to get quotient and remainder of number divided by 9.

For Division you'll use another type of representation which includes following three steps :

i) Split each dividend into a left hand part for the Quotient and right - hand part for the remainder by a slant line or slash. E.g. 13 as 1 / 3, 34 as 3 / 4 , 80 as 8 / 0.

ii) Leave some space below such representation, draw a horizontal line.

iii) Put the first digit of the dividend as it is under the horizontal line. Put the same digit under the right hand part for the remainder, add the two and place the sum  i.e., sum of the digits of the numbers as the remainder.



"Nikhilam" Division By 9 with Examples
05:54
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Vertically and crosswise ( Urdhva - Tiryagbhyam )
2 Lectures 04:37

Using this method you will be able to multiply any pair of two digit numbers quickly and accurately,

you'll learn this method in THREE steps:

Example :  Multiply 13 X 12 .

1st Step :  Multiply right most digits ( 3 X 2 = 6 )

2nd Step : Cross Multiplication and addition ( (1 X 3) + (1 X 2) = 3+2 = 5 )

3rd Step :  Multiply left most digits  (1 X 1= )

So Result is 156.


Preview 02:23

Using this method you will be able to multiply any pair of Three digit numbers quickly and accurately,

you'll learn this method in FIVE steps:

Example :  Multiply 132 X 124 .

1st Step :  Multiply right most digits ( 4 X 2 = 8 )

2nd Step : Cross Multiplication and addition of last two digits i.e. ( (3 X 4) + (2 X 2) = 12+4 = 16 (one is carry) )

3rd Step :  Diagonal multiplication and vertical multiplication also adding carry i.e. ((1X4)+(2X1)+(3X2)+1= 13)

4th Step :  Cross Multiplication and addition of First two digits  i.e. ( (1X2)+ (3X1) + 1 = 6)

5th Step :  Multiply Left most digits ( 1 X 1 = 1 

So Result is 16368.

"Urdhva" Multiplication of THREE digit numbers.
02:14
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Transpose and Apply ( Paravartya - Yojayet )
2 Lectures 07:16

Using this method , You'll be able to find quotient and remainder for the problems like :

1)

1234 ÷ 112

2) 11329 ÷ 1132

3)

12349÷ 133

4) 239479÷1203

This method includes minimum 2-3 steps and maximum number of steps depends on the digits of dividend.

"Paravartya" Division of any two numbers.
03:23

Using this method , You'll be able to find quotient and remainder for the problems of Algebra :


E.g.

 

 (x^3 – 4x^2 + 7x + 6)

-------------------------------

           (x – 2)


This methods includes 4 steps to solve the problem in matter of seconds.

"Paravartya" Division of Equations.
03:53
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One less than the one before ( Ekanyunena Purvena )
2 Lectures 06:24

The Sutra "Ekanyunena purvena " comes as a Sub-sutra to Nikhilam which gives the meaning 'One less than the previous' or 'One less than the one before'.

1) The use of this sutra in case of multiplication by 9,99,999.. is as follows .
      Method :

      a) The left hand side digit (digits) is ( are) obtained by applying the ekanyunena purvena i.e. by deduction 1 from            the left side digit (digits) .e.g. ( i ) 7 x 9; 7 – 1 = 6 ( L.H.S. digit )

      b) The right hand side digit is the complement or difference between the multiplier and the left hand side digit                (digits) . i.e. 7 X 9 R.H.S is 9 - 6 = 3.

      c) The two numbers give the answer; i.e. 7 X 9 = 63. 

  In this case Multiplicand is less than or equal to the multiplier.

"Ekanyunena" Multiplication by 9, 99 , 999... case 1
03:38

In this case Multiplicand is grater than multiplier.


"Ekanyunena" Multiplication by 9, 99 , 999... case 2
02:46
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Proportionality ( Anurupyena )
1 Lecture 03:48

There is a lag in Nikhilam method, and in this lecture you'll learn method to deal with the problem of multiplication with different bases.


"Anurupyena" Products Of Two Numbers near common Base.
03:48
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Vedic Addition and Subtraction ( Dot method )
2 Lectures 11:17

In this video you'll learn "Dot method" to do quick addition.

This method will accelerate your speed of addition.

Preview 06:35

In this lecture you'll learn technique of fast subtraction ,mixed addition and subtraction.

Fast Subtraction
04:42
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Miscellaneous Items
2 Lectures 09:16

Percentage is a very important chapter, In competitive exams percentage shortcut tricks play a vital role. In this lecture you'll learn shortcuts to find percentage, percentage increase and percentage decrease etc.


Percentage - Shortcuts
05:34

In this lecture you'll learn to find square of any number using duplex combination process.

Squaring (Duplex combination process)
03:42
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Practice Set.
3 Lectures 17:38

Expert Level Test.

TEST-1 ( Hard )
04:50

Intermediate Level test.

Preview 10:53

Easier than Test 1 & Test 2

TEST-3 ( Easy )
01:55
About the Instructor
Kamal Thakur
3.7 Average rating
22 Reviews
2,460 Students
4 Courses
Embedded System Engineer, Instructor

Hi,

My name is Kamal thakur, I am an Electronics Engineer and electronic hobbyist with an interest in making embedded systems, Robotics understandable and enjoyable to other enthusiasts of all experience and knowledge levels. 

Industrial automation engineer with knowledge from Information Technologies to Industrial Automation.

Experienced with project design, development & commissioning, product & application technical support, training & consulting services with international environment.

Always eager to learn, I invested a lot of time in learning and teaching, covering a wide range of different scientific topics. Being an electronics engineer, Today I am passionate about data science, artificial intelligence and deep learning for Robotics. I will do my very best to convey my passion for data science to you. I have gained diverse experience in this field. I spent one year doing research in machine learning, working on innovative and exciting projects.

Looking forward to working together!