The Complete Linear Motion Course

Define linear motion as movement in a straight line, with examples like a rock moving in a straight path. Recognize that this concept is everywhere and important to understand.

Differentiate vectors from scalars: vectors have magnitude and direction (shown with arrows), while scalars have magnitude only; examples include velocity and force as vectors, speed and mass as scalars.

Explore the difference between displacement and distance, defining displacement as a vector and distance as a scalar, and learn to read the diagram illustrating starting position, path, and net displacement.

Learn how to calculate average speed and average velocity in linear motion, and distinguish between speed (scalar) and velocity (vector) to apply the correct formula.

Learn the difference between instantaneous velocity and instantaneous speed, define speed at a specific instant, and compare displacement, distance, and time intervals.

Explore acceleration as the change in velocity over time and its vector nature, underscoring velocity's direction and magnitude, with applications to free fall and circular motion.

Apply key linear motion formulas to solve problems, including final speed v = u + a t and displacement s = u t + 1/2 a t^2.

Analyze real world linear motion problems by adding or subtracting vectors in the same or different directions to find the resultant vector, considering magnitude and direction.

Analyze a forward direction setup in linear motion with initial speed 24.6 and acceleration -4.92 until the final velocity is zero, yielding a displacement of 61.5 in about 5 s.

Compute the resultant displacement by combining east and west directions on a diagram, noting magnitudes and signs, using the video solution to practice positive and negative directions.

Solve the third linear motion problem by analyzing vector velocity in the same west direction, comparing 75 km west to 60 km west, with guided practice and Q&A.

Analyzes a car accelerating from 80 to 100 km/h in 200 m, converts to m/s, and uses v^2 = v0^2 + 2 a s to find a ≈ 0.69 m/s^2.

Follow along as you solve a linear motion problem by converting minutes to seconds and kilometers to meters, then apply the formula to compute acceleration and displacement.

Learn how to approach the question with two different solution methods, as this video introduces the split into two parts and explains the instructor's approach to solving the problem.

Solve two linear motion problems using v = u + at and s = ut + 1/2 at^2, finding speed after 5 s is 30 m/s and distance is 100 m, with correct units.

Demonstrate solving a uniform acceleration problem from 10 m/s to 30 m/s in five seconds, and verify the 100 m distance using different formulas.

Solve a conveyor belt problem in an electronic factory by applying v^2 = u^2 + 2 a s with u=0, a=0.45 m/s^2, s=10 m, yielding v=3 m/s forward.

This video solution solves a problem comparing sober and drunk drivers. It converts 63 km/h to 17.5 m/s, uses reaction times 0.3 s and 1.2 s, and yields 16 m.

Watch the second video for a shorter, more efficient solution to the linear motion problem, then convert speeds to meters per second and apply a direct formula for displacement.

Analyze the question to extract velocity 10 m/s, distance 100 m, and time 35 s. Compare the travel time to 35 s to decide if it arrives on time.

An optional second video presents a shorter, more efficient solution for the final exam in the complete linear motion course, covering unit conversion and a direct formula to compute displacements.

Complete the linear motion course and apply the knowledge to problems; you will not receive certification, join the Q&A, and enjoy free, no-cost lecture videos and quizzes with updates.