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Second Law of Thermodynamics
Rating: 4.3 out of 5(3 ratings)
1,054 students

Second Law of Thermodynamics

Heat Engine, Heat Pump and Refrigeration system
Created byBasawraj Racheti
Last updated 2/2023
English

What you'll learn

  • To study the aspects of Second law of Thermodynamics
  • To understand the statements of Second law of thermodynamics
  • To get the concept of Equivalence of Kelvin-Planck and Clausius Statement
  • To get the idea of COP of Heat pumps and Refrigeration
  • To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator
  • Get idea about Carnot’s theorem and Carnot Cycle.
  • Know the working principle of Heat Engines, Heat Pumps and Refrigerators .

Course content

1 section • 6 lectures • 1h 36m total length

  • Numericals on Steady Flow Energy Equation (SFEE)16:55

    Apply the steady flow energy equation to an oil cooler to compute cooling water flow; then find turbine exhaust temperature in a gas-turbine problem.

  • Lecture 2: Second Law Of Thermodynamics20:22

    Explore the second law of thermodynamics, including kelvin-planck and classical statements, their equivalence, and the roles of heat engines, refrigerators, and heat pumps, plus reversibility and irreversibility.

  • Lecture 3: Carnot Engine24:28

    Explore Carnot's theorem and cycle, showing no heat engine between two reservoirs beats a reversible engine. Examine isothermal and adiabatic steps and link to heat pumps and refrigerators COP.

  • Lecture 4: Heat Engines and COP for Heat Pumps and Refrigerators14:27

    Explore the second law with heat pumps and refrigeration, detailing evaporator, condenser, compressor, expansion valve, and COP formulas; compare heating and cooling modes and Carnot efficiency.

  • Lect 5: Numericals on COP and Efficiency- II7:55

    Solve numerical problems on the second law, calculating the refrigeration coefficient of performance, heat pump heat transfer, and engine efficiency from given data.

  • Numericals on Efficiency and COP -III12:32

Requirements

  • Engineering Physics , Engineering Chemistry, Basic Mechanical Engineering

Description

Course Contents as per syllabus :

Equivalence of Clausius and Kelvin Planck Statement, PMM I and II, Concept of Reversibility and Irreversibility.

Course Objectives:

•To study the aspects of Second law of Thermodynamics

•To understand the statements of Second law of thermodynamics

•To get the concept of Equivalence of Kelvin-Planck and Clausius Statement

•To define Perpetual Machine of IInd Kind (PMM-II)

•To Study Carnot theorem and Carnot Cycle

•To get the knowledge of Heat engine and its efficiency

•To compare Heat pumps and Refrigeration system

•To get the idea of COP of Heat pumps and Refrigeration

•To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator

Brief description about  Heat Engine, Refrigerator and Heat pump :


HEAT ENGINE

Based on Kelvin- Planck’s Statement.

It is a device that converts heat to work.

In case of heat engine, efficiency is defined as ratio of work done to heat energy supplied.

Here important criteria is net work done.

Work done by the engine =W = (Q1 – Q2)

Efficiency = Work done / Heat supplied

Efficiency = W / Q1 = (Q1 – Q2) / Q1

                      = (T1-T2 ) / T1

                      = 1 – ( T2 / T1)


REFRIGERATOR

Based on Clausius Statement.

In case of a refrigerator ,COP is defined which is the ratio of heat absorbed (refrigeration effect) to work done on the system ,Here the important criteria is heat absorbed as refrigeration effect.

Work Done on system = (Q1 – Q2)

COPR = Desired Effect / Work done

            = Q2 / ( Q1 – Q2)

           = T2 / ( T1-T2)

COP is reverse of Efficiency


HEAT PUMP

Based on Clausius Statement.

In case of a heat pump ,COP is defined which is the ratio of heat rejected (refrigeration effect) to work done on the system. Here the important criteria is heat rejected as refrigeration effect.

Work Done on system = (Q1 – Q2)

COPHP = Desired Effect / Work done

                = Q1 / ( Q1 – Q2)

               = T1 / ( T1-T2)

COP HP = COPR + 1


Course Outcomes :

Learner will be able to

•Get idea about limitations of First law of Thermodynamics.

•Can compare between Kelvin and Clausius Statements.

•Understand various statements of Second law of Thermodynamics.

•Have clear idea about Kelvin and Clausius Statement.

•Get idea about Carnot’s theorem and Carnot Cycle.

•Know the working principle of Heat Engines, Heat Pumps and Refrigerators .

•Find out Efficiency of Heat Engines and COP of heat pumps and refrigerators.


Who this course is for:

  • Second year Mechanical Students and also for all mechanical students

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