
Meet a Russian mathematics teacher from Mipt who explains the unified state exam and its difficulty. Learn about his 100-point achievements and his math and technology passions.
Explore problems with parameters across equations, inequalities, systems, and function properties, and learn graphical, analytical, and functional methods to solve them.
Explore linear equations with a parameter, cases with one, no, or infinitely many solutions. For a ≠ −2, x = a + 2; for a = −2, any solution.
Solve problems with parameters to train your brain through three main approaches, choosing the best strategy from a toolbox of tools like mathematicians.
Explore solving linear equations with parameters, including substitution and division caveats, critical values like a=0 and a=-2, and cases with no, infinite, or unique solutions.
Analyze a system of linear equations to find a values that yield no solutions; a = -4 gives no solution, a = -2 yields infinitely many, otherwise a unique solution.
Analyze linear inequalities by three cases for a: positive, negative, and zero; note sign flips when dividing by negatives and the empty set for a=0; deduce a<2.
Learn how the discriminant decides real solutions of quadratic equations with a parameter a, yielding two, one, or no solutions, and note the linear case when a equals zero.
Apply Vieta's formulas to a quadratic with parameters, form a root pair, and require positive discriminant to find parameter values, such as a = 4 and a = -3/8.
Apply Vieta's formulas to determine when both roots are positive by ensuring the sum and product of the roots are positive, avoiding cumbersome discriminant inequalities.
Learn to solve quadratic inequalities with a parameter by analyzing the parabola, using discriminant cases and a number line to determine the solution sets for a and x.
Explain quadratic inequalities with a parameter, requiring a solution segment longer than six; use discriminant and root difference to derive a less than minus one or a greater than three.
Consider a quadratic ax^2+bx+c with a>0; the parabola opens upward, its vertex is at x=-b/(2a) and y=-D/(4a), and if f(t)<0 for some t, the nailing theorem guarantees two distinct roots.
The quadratic in x opens upward since a^2 - a + 1 is positive for all a, and x = 1 yields f(1) < 0, implying two distinct roots.
Use the nailing theorem to locate roots of a quadratic relative to 2, deriving a < -4, then for the threshold 1 obtain -1 < a < 0.
Determine parameter values for which the quadratic’s roots exceed -1 or 1/2, using discriminant, vertex position, and unified inequalities; consider distinct and equal-root cases to obtain the range of a.
Determine a for which x^2 + a x + 4 has roots in [1,3], using discriminant nonnegative and a vertex between 1 and 3, yielding a in -13/3 to -4.
This course will challenge your knowledge in high-school mathematics. You will learn new ways of solving problems with parameter and comparing ways of solving these problems and choosing the best one.
This course is first of all made for school and university teachers and technical university students, but anyone who wants to put their knowledge of basic mathematics in systematic order can take it.
The course covers three main ways of solving problems with parameter:
Analytical method.
You will learn about:
linear equations and inequalities with parameter
systems of linear equations and inequalities with parameter
rational equations and inequalities with parameter
quadratic equations and inequalities with parameter
theorems about positions of the roots of quadratic equations and inequalities with parameter
problems reducible to quadratic equations and inequalities with parameter
Graphical method.
You will learn about:
graphs of linear, quadratic, rational, modular, irrational, exponential, logarithmic and trigonometric functions
transformations of graphs of functions
graphs of equations and inequalities
using graphs as a visualisation tool to solve problems with parameter
Functional method.
You will learn about:
monotonous functions
limited functions
even\odd functions
using properties of functions to solve problems with parameter
In conclusion you will face some problems solvable in every mentioned way and learn to compare different ideas and choose the one that fits the best for every unique situation.