Use superposition to compute the total electric field from two equal, opposite point charges by summing their vectors and analyzing both magnitude and direction.

Calculate the dipole electric field at three points—midpoint, above midpoint, and on the axis near the negative charge—by vector addition of the charges using E = k q / r^2.

Illustrate how two parallel plates create a uniform electric field between them with magnitude sigma/epsilon0, directed from the positive to the negative plate, while outside fields cancel.

Explore the motion of charged particles between parallel plates, using constant acceleration and kinematic equations to analyze trajectories, speeds, and times.

Analyze how conductors rearrange surface charges to cancel internal fields, keep the interior field zero, create perpendicular fields at the surface, and shield cavities from external influences.

Solve six multiple-choice problems on electric fields, using the attached PDF to practice on your own, then watch the solutions in the following video.

conservative forces, including gravity, spring forces, and electrical forces, have associated potential energies; their work is path-independent, as shown by the capacitor example where only parallel components contribute.

Compute electrical potential energy between point charges using U = k Q1 Q2 / r, and compare applied work with the electric field, noting sign of charges.

Apply the conservative electric force: work equals negative change in potential energy; initial U is zero, final U is 0.024 J, giving -0.024 J of work.

Use conservation of energy for electric problems, since the electrical force is conservative, converting electrical potential energy to kinetic energy as a moving charge accelerates to its speed far away.

Explore how two point charges create electrical potential energy. Learn V = k q / r, U = q V, and volts as joules per coulomb.

Describes a positive point charge creating equipotential surfaces from 40 v to 5 v, and shows the electric field pointing away and perpendicular to surfaces from high to low potential.

Analyze parallel plates to obtain uniform field of 1200 V/m downward, with equipotential surfaces perpendicular to the field and a change from +30 V to −30 V across 5 cm.

Charges reside on the surface of a conductor and distribute unevenly near sharp edges. The electric field inside is zero, so the conductor maintains the same potential throughout.

The lecture presents quiz solutions on electric force, fields, and potential. It explains how potential energy changes as charges move, zero potentials, and equal-potential lines in a uniform field.

Using Gauss's law, a uniformly charged 2D plate produces a perpendicular field of magnitude sigma divided by two epsilon0 that points away for positive sigma and is independent of distance.

Relate capacitance to charge and voltage as the constant of proportionality, C = Q/V, and note for parallel plates C = ε0 A / d, with air or dielectric.

Capacitors in parallel share the same voltage; with 10 V, 10 µF and 40 µF yield 100 µC and 400 µC, totaling 500 µC, with C_eq = 50 µF.

See how a battery powers charging of a capacitor to store electrical potential energy, and learn three equivalent energy formulas: 1/2 qV, 1/2 CV^2, and Q^2/C.

Analyze electric flux in a uniform field using magnitude, area, and angle; compare electric fields and potentials between point charges and explore energy exchange in electrostatic interactions.

Compare parallel plate capacitors with twice the area and thus twice the capacitance, same spacing. Use energy conservation and q ΔV to compute kinetic energy gain and electric-field work.

Use superposition to compute potentials from two equal point charges, and apply uniform field and parallel plate capacitor concepts to find the electric field magnitudes.

Apply Gauss's law to a conducting sphere and shell to find electric field in between, inside zero, and outside conductor; total charge -1e-9 c yields ~144 n/c at 0.25 m.