New SAT Math Course

Master inverse operations to solve basic linear equations by moving terms across the equals sign and applying opposite operations, like adding or subtracting seven and multiplying or dividing by seven.

Explore a basic linear equation example, demonstrating how substituting positive five affects the expression and yields the solution five.

Practice solving a basic linear equation by isolating x, moving terms to the right-hand side, and dividing by four to find the value of x.

Solve a basic linear equation example by outlining steps to reach a positive solution, yielding the answer 10 and the correct choice C.

Solve a linear equation by moving terms to the right-hand side and multiplying by two, yielding x = 24.

Learn how to solve an equation with parentheses by moving unrelated terms to the right-hand side. Observe how the steps simplify to 15x and reveal the solution step by step.

Solving equations with parentheses by moving terms to the left and right sides, applying distribution, and isolating x. The example highlights handling negatives, combining like terms, and solving for x.

Learn to solve equations with fractions by making the sides share the same numbers, then multiply to get x/6 = 4 and x = 24.

Learn to solve simple linear equations with fractions by using a common denominator and a concise, single-line representation to simplify the equation.

Solve equations that contain fractions by finding a common denominator, clearing fractions, and isolating x on both sides to obtain a solution.

Learn to solve equations by cross multiplying, isolate x by moving terms to the left side, and divide on the right to get the solution.

Learn to solve equations by cross multiplying, balance left side variables with right hand side values, and isolate x to obtain x equals negative four.

Discover the relationship between two terms in a linear equation type 1 example. The caption shows one term equals two times the other, guiding the solution.

Move through a linear equation type 1 example by transforming expressions and applying basic arithmetic, as shown with evaluating 16 plus four times three to find the solution.

Solve linear equation type 2 examples by setting 3x+2=5 to find x and then evaluate 15−6x to confirm the result.

Explore a linear equation type 2 example by solving 5x - x = -2 and deducing the value of 15x from the relationship between 5x and 15x.

Solve a linear equation type 2 example by linking expressions like 2 x times 5 to determine x and verify the resulting values.

Demonstrates a linear equation type 3 example by exploring the reciprocal relationship between A/B and B/A and showing how to manipulate both sides to reach a solution.

this linear equation type 3 example teaches solving a ratio A over B by transforming to B over A, using previous question strategies, and leads to the final answer C.

Explore a linear equation type 3 example, noting no reciprocal relationships and that A over B remains the same, yielding a simple relation.

learn why absolute value expressions are always nonnegative and how they equal zero only when the inner expression is zero, illustrated by 3 - x = 0.

Explore how inequalities differ from equations and how multiplication or division by a negative number reverses the inequality. Solve a type 1 inequality example with the variable on the left.

Explore solving inequality type 1 example 2 by rearranging terms, applying division by a negative with inequality reversal, and concluding the solution is x < -5.

Solves inequality type 2 example 1 by guiding students to determine the least possible value of an expression, balancing sides, with the least value 11.

Analyze inequality type 2 by comparing 2x-3 and 2x+1 to determine the greatest possible value of 2x+1 under a bound, illustrated with a bound of 10.

Analyze inequality type 3 examples involving x and y, focusing on absolute value relationships and case analysis to determine which statements must be true.

Explore linear functions by linking the independent variable x to dependent variable y, and learn how the slope m, positive or negative, governs the graph’s direction and rate of change.

Demonstrate a linear function through a demo, observe positive results, and explain how the graph rises as the input increases.

Explore the introduction of a linear function by examining negative values and their relation to the x axis in a practical demo.

Introduce linear function concepts by identifying positive and negative slopes, explaining how a slope indicates upward or downward trends, and combining ideas to analyze the resulting curve.

Introduce linear functions by sketching a downward-sloping line with a negative slope and negative y-intercept, illustrating how the graph goes down and lies below.

The lecture explains a restaurant cost example using a linear function y = mx + c, with slope 15 and intercept 150, where n represents the number of waiters.

Model a linear function y = 0.6x + 29, with x as years since 2000, and interpret the slope as a 0.6 increase per year in the population.

Model a linear inequality word problem about buying coke at $5 and nuts at $10, where x is Coke and nuts are twice x, with total cost 35 to 45.

Compute the slope from two points and derive the line's intercept, then express the result in slope-intercept form as y = 2x + 4.

An introduction to a linear function word problem about earnings: 40 dollars per day plus overtime at 12 dollars per hour to compute daily income.

Model a buying problem with linear inequalities, using x for casual shirts at $20 and y for formal shirts at $25, with at least 15 shirts and a $350 budget.

Master the elimination method to solve systems of linear equations by multiplying equations to cancel a variable, then substitute to find x and y.

solve a system of linear equations to determine the numbers of waiting and fighting games, given five total games and a 46-dollar total, with waiting games priced at 10 dollars.