
Introduces trigonometry as the branch of mathematics for measuring angles and sides, and defines angle concepts, generating line, initial line, and the annulus around a given area.
Explore the core trigonometric ratios in a right-angled triangle, including sine, cosine, and tangent, defined as opposite over hypotenuse, adjacent over hypotenuse, and opposite over adjacent, with links to Pythagoras.
Explore how in a right triangle the non-right angles are complementary and how sine, cosine, and tangent relate to complements, including sin theta = cos(90 degrees minus theta) and tan theta = cot(90 degrees minus theta).
Explains the trigonometric ratios for angle 0 and 90 degrees in a right triangle, deriving sine and cosine values (sine 0 = 0, sine 90 = 1, cos 0 = 1, cos 90 = 0) and noting tangent is undefined at 90 degrees.
Explore the trig ratios for 30 and 60 degrees by deriving sine, cosine, and tangent values in a right triangle and examining base and height relationships.
Explores trigonometric ratios of 45 degrees, deriving sine and cosine as 1/2 and establishing cosecant, secant, and tangent values for the 45-degree angle.
Explore and prove the standard trigonometric identities sin^2 x + cos^2 x = 1 and tan^2 x + 1 = sec^2 x using a right-triangle approach.
Explore three angle measurement systems: degrees minutes seconds, grads, and radians, covering full rotation, right angles, and the arc-length definition, with interconversions between these units.
Apply Pythagoras to a right triangle with AB 24 cm and BC 7 cm to obtain AC = 25 cm, then find sin and cos as 7/25.
Apply pythagoras to solve a right triangle, confirm the 5-12-13 triple, and determine the sides and angles. The solution shows angle B equals the corresponding angle, their difference zero.
From sin A = 3/4 in a right triangle ABC, use Pythagoras to find AB = sqrt(7), then cos A = sqrt(7)/4 and tan A = 3/sqrt(7).
Solve a right triangle in chapter eight trigonometry using the hypotenuse squared equals sum of squares, then compute sine from opposite over hypotenuse.
Solve a right-angled triangle problem from ex 8.1 by finding x=5 and y=12 with hypotenuse 13 using x^2 + y^2 = 13^2, then apply sine ratios and inverse sine.
In a right triangle ABC, if cos A equals cos B, then A equals B, so opposite sides are equal and the cosines match.
This lecture solves exercise 8.1 problem 7 from chapter 8 trigonometry, deriving sine and cosine values from cos theta equals 7/8 using pythagorean identities and exact fractions.
solve chapter 8 trigonometry ex 8.1 q8 by analyzing a 3-4-5 right triangle to derive sin and cos from opposite and adjacent over hypotenuse, then apply pythagoras and verify identities.
solve exercise 8.1 question 9 in chapter 8 trigonometry by determining sine, cosine, and tangent of angle C in a right triangle using opposite, adjacent, and hypotenuse.
Solve a 5-12-13 right triangle from Ex 8.1 Q10, and obtain sin B = 12/13, cos B = 5/13, and tan B = 12/5.
Analyze true or false statements about sine, cosine, and tangent in 0 to 90 degrees, focusing on their ranges and angle relationships in NCERT chapter 8 Ex 8.1 Q11.
Explore solving trigonometry problems from NCERT class 10 chapter 8, exercise 8.2, using known values for 30°, 45°, 60° and table values to simplify sine and cosine squares.
Tackle chapter 8 trigonometry problems from class 10, exercise 8.2 question 2, by evaluating expressions at 30°, 45°, and 60° and verifying trigonometric identities to choose the correct option.
Apply trigonometric identities to simplify expressions, using sin(90°−x)=cos x and cos(90°−x)=sin x to evaluate angles like 18°, 72°, and 64°, yielding cancellations and zero in cases.
The lecture demonstrates simplifying trig expressions using identities, especially sine of (90 degrees minus x) relationships, as applied in exercise 8.3 question 2, and verifies resulting equalities to zero.
Solving ex 8.3 q3, this chapter on trigonometry expresses both sides in degrees, applies a key formula to simplify, and derives a clear solution.
Apply the 90 degrees minus B relation to rewrite expressions, compare left and right sides, and deduce that B equals 90 degrees.
Solve chapter 8 trigonometry ex 8.3 q5 by applying angle relations and converting to a 90-degree minus expression, yielding 22 degrees.
Examine chapter 8 trigonometry, exercise 8.3 question 6. Use A + B + C = 180 degrees to manipulate expressions and derive a trigonometric relationship.
Demonstrates solving exercise 8.3 question 7 by applying sine and cosine relationships and 90-degree complements to simplify expressions for angles such as 67°, 75°, and 45°.
Use trigonometric identities to express sine in terms of cosine via sin^2 x + cos^2 x = 1, obtaining sin x = sqrt(1 − cos^2 x).
Express trigonometric functions in terms of sine and cosine using sin^2 x + cos^2 x = 1. Derive tan, sec, csc, and cot from these expressions via algebraic substitutions.
Explore solving trigonometry expressions by applying complementary angle identities and reductions from angles like 63°, 27°, and 73°, to simplify to a basic value.
Apply the sine rule to a chapter 8 trigonometry problem, use sin(90°−25°)=sin65° to simplify, and solve exercise 8.4 question 3 ii.
Solve exercise 8.4 question 4 from chapter 8 trigonometry by evaluating trigonometric expressions with angle substitutions, including 45 degrees, and identify the correct options.
Apply trigonometric identities to simplify expressions involving cos, solving exercise 8.4 problem i and showing how a cos-based ratio reduces to a simpler form.
Explore proving a trigonometric identity from NCERT class 10 maths chapter 8 ex 8.4 q5(ii) by simplifying sine and cosine expressions to show equality of both sides.
Explore chapter 8 trigonometry by solving exercise 8.4 question 5 iii, simplifying trig expressions and equations with cosine, sine, and careful handling of signs and squares.
Explore trigonometric simplification using the identity sin^2 x + cos^2 x = 1. Rewrite 1 − cos^2 x as sin^2 x, factor as (1 − cos x)(1 + cos x), cancel common factors, and arrive at a simplified form.
Explore solving a trigonometry identity from chapter 8, exercise 8.4 question 5, transforming expressions with minus signs and squares to verify a valid identity.
Explore chapter 8 trigonometry by solving exercise 8.4 question 5. Learn to evaluate and simplify trigonometric expressions and apply sign rules.
Prove trigonometric identities and simplify expressions involving square terms in chapter 8, exercise 8.4, question 5, part viii.
Prove and simplify a trigonometric identity from exercise 8.4, demonstrating the equivalence of left and right sides through algebraic manipulation of sine and cosine terms.
Explore solving and proving trigonometric equations from exercise 8.4, focusing on radicals and squares to establish equality.
Solve a right-angled triangle problem from class 10 trigonometry, expressing the target value in terms of the opposite side and the hypotenuse using Pythagoras and square-root steps.
Explain solving the rd sharma class 10 chapter 5 exercise 2 question 04, simplifying a trigonometric expression involving one minus cos squared over sin squared to a value.
Solve a trigonometry problem from RD Sharma class 10 by using a triple-angle relation to find x, with 3x equal to 60 degrees, yielding x equals 20 degrees.
Solve a classic class 10 maths trigonometry problem from RD Sharma chapter 5 ex 2 q 21, involving angles 30 and 60 degrees.
Solve a class 10 trigonometry problem using sine and cosine relations to determine angles, concluding angle A is 45 degrees and angle B is 15 degrees.
Solves RD Sharma class 10 chapter 5 exercise 5.3 question 13 on trigonometric identities, using angle relations around 60° and 90° to simplify expressions involving sine, cosine, and tangent.
Solve question 37 from RD Sharma class 10 chapter 6 ex 6.1 by simplifying a square-root trigonometric expression involving sine, cosine, and the reciprocal of cosine.
Derive and solve a quadratic by forming two equations with x and constants, squaring, and adding them to isolate x and obtain its values.
Explore solving the exercise 6.1 question 87 from RD Sharma Class 10, focusing on equations involving x squared and y squared and their squaring relationships.
Apply trig identities to express angles such as 75° and 15° using 90° minus a value, and determine valid solutions in 0–30°.
Solve a RD Sharma class 10 trigonometry exercise from chapter 6 ex 6.2 q12, using sine and cosine to obtain a result involving square root of two and i.
NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry is a self-paced course is designed to help CBSE Class 10 students to understand concepts and application through videos. You can view these Video lectures as many times as you want to clear the concepts.
Video Solutions has been prepared strictly as per latest syllabus issued by CBSE for the students associated with Class X.
Few of the features of the course:
Concepts covered:
Bonus: Selected RD Sharma Class 10 solutions of Trigonometry