
Wraps up resistor-inductor circuits by solving a new step voltage source case and reviewing the current–voltage relation V = L di/dt, energy storage, and time constants.
Set up a resistor-inductor circuit driven by a unit step to show t<0 and t>0 behavior, with initial current from the 50 volt source and gradual rise after turn-on.
Determine the inductor current as t approaches infinity with both sources on, treating the inductor as a short and using Ohm's law to reach 50 amps.
Zero the sources; resistance seen by the inductor is 1.5 Ω from 2 Ω and 6 Ω in parallel, so tau = 3 H / 1.5 Ω = 2 s.
Select the final equation and plug values to compute inductor current, starting at 25 A, ending at 50 A, with a 2 s time constant under a step input.
Apply v = L di/dt to determine the voltage across an inductor from the current’s rate of change. The lecture demonstrates slope-based calculations for voltage drops across inductors.
Explore how energy stored in an inductor follows E = 1/2 L I^2, with current through the inductor determining the stored energy as time goes to infinity.
Apply the step function to on/off sources, compute inductor voltage from current, and show capacitors invert these ideas, with voltage that cannot change instantly.
Day 28 of Linear Circuits. Inductors are one of the three passive circuit components (along with resistors and capacitors). However, their operation and behavior is often shrouded in mystery. After seeing how to find the initial and final values of currents and voltages, today, we introduce a solution process that uses this information for any resistor-inductor circuit. Here, we include even more examples of using our process to solve resistor-inductor circuits.
The material covers all of the lecture material from an twenty-eighth lecture in a traditional, sophomore-level linear circuits class.