
Rewrite power equation to distinguish absorbed from generated power in circuits, using P = V I with delta V and current into the positive terminal for loads, motors, and lights.
Ground at 0 V, a -1 V source and a 4 V source establish 3 V across a 470 ohm resistor; Ohm's law gives 6.38 mA.
Explore power equations and Ohm's law, deriving P = I^2 R and P = V^2 / R from V = IR, noting these formulas apply only to resistors, not sources.
Explore power in circuits, its unit the watt, equal to one joule per second, and the universal p = v i form, with p = i^2 r for resistors only.
Explore a two-source circuit where one battery generates power and the other absorbs it, linked by a low-resistance cable. Use Ohm's law to compute current and verify power balance.
Analyze a current source circuit with a 10 ohm resistor, showing 40 W absorbed by the resistor and 40 W generated by the source, ensuring power sums to zero.
Compute power in a circuit with a 10-ohm resistor and a 2-amp current source, yielding a 20-volt drop and 40 watts absorbed, then verify by power balance.
Day 4 of Linear Circuits. Students are introduced to electrical power. Many students will already be familiar with the equation P = V I. We rewrite this equation to make it easier to use and provide you with lots and lots of examples.
The material covers all of the lecture material from a fourth lecture in a traditional, sophomore-level linear circuits class.