
Master water treatment and distribution math for certification, taught by a certified water operator, by learning surface area to volume, pressure flow, detention time, chemical dosage calculations, and velocity.
Compute surface area and paint required for a 140 ft fence with 6 ft height, two sides, subtracting 12 ft and 4 ft gates, at 100 ft² per gallon.
Compute roundup by taking fenced area 240×140, subtract the circle area 0.785×50^2, then divide by 4000 to estimate about 7.9 gallons (≈8).
Compute the tank’s side area by using circumference equals pi times diameter; with a 50-ft diameter and 30-ft height, paint 47.1 gallons at 100 ft² per gallon.
Compute volume of a sedimentation basin by multiplying length, width, and height, then convert cubic feet to gallons using 7.48 gallons per cubic foot; for 50×20×15 you get 112,200 gallons.
Compute tank’s volume using V = 0.785 × diameter^2 × height for a 100 ft diameter, 50 ft high tank, then convert with 7.48 gal/ft^3 to about 2.94 million gallons.
Compute the water volume from intake to the treatment plant for a three-mile, 18-inch pipe using the volume formula, convert to cubic feet, and then to gallons.
Calculate the water volume in a 20 ft diameter tank with 19 ft water using V = 0.785 d^2 h to obtain cubic feet, then convert to gallons at 7.48 gal/ft³.
Calculate the pressure at the bottom of a 30 ft water tank using two formulas from the formula sheet; both yield about 13 psi.
Convert the 200 psi pump pressure to water head using 2.31 ft/psi (or 0.433 psi/ft), showing that the well depth is 462 feet.
Convert a flow rate from 800 gallons per minute to million gallons per day using 60 minutes per hour and 24 hours per day, then validate with back-calculation.
In flow problem #2, a 100 ft diameter tank with 30 ft water is pumped at 750 gpm for eight hours. About 6.1 ft is removed, leaving roughly 24 ft.
Calculate detention time for a 35-ft diameter, 10-ft clarifier at 0.3 MGD using cylinder volume and detention time formulas, yielding about 5.75 hours; check shows 8 hours equals 0.216 MGD.
Compute detention time for a basin using volume = length × width × depth; convert to gallons with 7.48 gal/ft^3 and divide by 0.25 million gal/day to get 8.6 hours.
Apply the pounds per day formula from million gallons a day flow, using mg/L dose, water weight per gallon, and purity to calculate chlorine usage.
Calculate chlorine dose in pounds per day for a 4 million gallon per day flow using 3 mg/l, applying the 8.34 conversion factor and 100% purity.
Calculate the aluminum sulfate feed rate for a 5 million gal/day plant at a 12 mg/L dose, using £5 per gallon and £8.34 per gallon, yielding 101 gallons per day.
Calculate pounds per day for a 4 million gallon reservoir using a 0.3 mg/L dose and 8.34 pounds per gallon, then verify with an inverse mg/L calculation.
Calculate the alum dose in mg/L from a 2.2 million gallons per day flow using mg/L = pounds per day divided by million gallons per day × 8.34.
Calculate velocity in feet per second for flow of 1 million gallons per day through an 18-inch pipe using area velocity formulas from the formula sheet, yielding about 0.877 ft/s.
Calculate velocity in a ten-inch pipe with a flow of 5 cfs by dividing flow by area, converting diameter to feet, using area = 0.785 diameter squared, yielding 9.18 ft/s.
Learn Water Treatment and Distribution Certification Math for Grades 1 and 2. This course is also relevant to Wastewater Operator Certification Math. Be prepared when walking into your certification exam. This 2 hour course contains 21 questions covering topics you may encounter on your exam. The topics covered are surface area, volume, pressure, flow, detention time, chemical dosage calculations, and velocity. This course is slow paced and detailed, working problems from start to finish. If your interested in becoming a certified water treatment or distribution operator this course is a great start to understanding questions you may run into on an exam. The course content is 21 individual lectures. Each lecture covering a topic. The questions are written and easy to read. Most questions include a visual representation of the problem and also a formula that is provided when taking a certification exam. Courses use to be offered only twice a year but are now are readily available at testing centers to complete at your own convenience. Scratch paper is provided and you are also provided a calculator. Exams do have a time constraint. The exam is divided into three sections. There is a true/false section, a multiple choice section, and a math section. This course focuses on the math section. The math section is a multiple choice answer format. This is to your advantage because you are able to check your answer against the four or five possible answers. If your answer is there, great! If there is one that is close, maybe a simple rounding error, awesome! If none of the answers are even close to yours, then you know that it is best to rework the problem till you find an answer that is yours or close to it. Thank you for taking the time to read this course description and if you decide to enroll, we will see you in the next video!