
The lecture derives the average memory access time for cache and RAM under simultaneous and hierarchical memory organizations, showing results of 24 ns and 25 ns respectively.
explore memory hierarchy with cache, main memory, and disk; apply hit ratios 0.9 and 0.8 to derive 220 ns average access time.
Analyze a two-level cache system to calculate average memory access time, using L1 and L2 hit ratios, access times, and main memory assumptions.
Calculate disk capacity by multiplying platters, surfaces, tracks, sectors, and bytes; with 32 platters, two surfaces, 64 tracks, 256 sectors, and 512 bytes, you get 2 power 29 bytes.
Compute total sectors on the disk pack from platters, surfaces, tracks, and sectors per track. Determine that the sector number uses twenty bits to address all sectors.
Compute the maximum recording density on the innermost track with a 21 cm diameter; 128 kilobytes per 66 cm yields about 1.94 kilobytes per centimeter.
this lecture derives the hard disk data transfer rate by linking track capacity and rotation speed: 128 KB per rotation at 3600 rpm yields 7,680 KB/s.
Calculate the average disk access time for a 250-byte read by summing average seek time, average rotational latency, and data transfer time. The example yields 300 milliseconds at 600 rpm.
Calculate time to read one megabyte from the outermost track by summing seek time, rotational latency, and data transfer time, using 6000 rpm and 20 sectors per track, totaling 13.5 ms.
Learn to map a sector number to its disk address, cylinder, surface, and sector within, using 1260 sectors per cylinder and 63 per surface, counting from zero.
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Which text book should you refer ?
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