
Solve a linear equation by distributing factors in parentheses, combining like terms, and isolating x to arrive at the final answer x = -5.
Discover how to solve a linear equation by distributing and combining like terms, and isolating x to obtain x equals minus one.
Master solving a linear equation in college algebra by moving x terms to one side, turning 7x − x into 6x, and dividing by 6 to obtain x = 11/6.
Solves linear equations in college algebra by isolating x in 3x + 5 = 2x + 13. Subtract 2x and 5 to find x = 8.
Solve a linear equation by adding five to both sides and dividing by seven to find x; the example 7x - 5 = 72 yields x = 11.
Distribute on the left and right sides, combine like terms, move all x terms to the left, and isolate x to get x equals 9.
Clear fractions by multiplying by the least common denominator to simplify a linear equation with fractions. Then distribute, combine like terms, and isolate x to find x equals 12.
Learn to solve a linear equation with fractions by multiplying by the least common denominator, distributing, and isolating x to obtain x equals negative 20.
Eliminate fractions in a linear equation by multiplying both sides by the least common denominator (12), then distribute and combine like terms to isolate x, yielding x equals -12.
Download the assignment below:)
Solutions are on the second page.
Learn that rational equations are equations with fractions, solve by clearing fractions, and check undefined values when denominators become zero, like x cannot be 0, 2, or -2.
Download the assignment below:)
Solutions are on the second page.
Practice adding and subtracting complex numbers by distributing the negative and combining real and imaginary parts; for example, 3 + 2i - (-4 - 6i) simplifies to 7 + 8i.
Distribute the negative, recognize the imaginary unit i, and combine like terms to add and subtract complex numbers, yielding the real part four and imaginary part five i.
Multiply complex numbers by foiling, then apply the conjugate trick to simplify a product by squaring the real and imaginary parts, yielding 29 in the example.
Multiply complex numbers using foil, apply i squared equals minus one, and use a conjugate shortcut to simplify to fifteen.
Download the assignment below:)
Solutions are on the second page.
Learn to divide complex numbers in college algebra by multiplying by the conjugate, applying foil, and expressing the result as (a^2+b^2) in the denominator with a+bi form.
Factor the quadratic x^2 + 4x + 3 into (x+1)(x+3) and apply the zero-product property to solve for x, yielding x = -1 or x = -3.
Use completing the square to solve the quadratic x^2+4x-7=0 by isolating x-terms, forming a perfect square, and obtaining x = -2 ± sqrt(11).
Complete the square to solve the quadratic: get x^2 - x = 1/8, form a perfect square, and apply plus/minus roots to find x = 1/2 ± sqrt(3/8).
Apply the quadratic formula to solve a quadratic by identifying a, b, and c, computing the discriminant, and simplifying to roots 1 and 1/2.
Download the assignment below:)
The solutions are on the second page.
Solve radical equations by isolating the square root, squaring both sides, and solving the resulting quadratic, then verify solutions in the original equation using the zero product principle.
Learn to solve equations with square roots by squaring both sides, factor the resulting quadratic, and verify that x = 8 is the valid root.
Isolate one square root, square both sides, and use the (a−b)^2 expansion to solve equations with two square roots. Verify the original equation to confirm or expose no solution.
Solve for x by isolating square root terms, square both sides, apply foiling, obtain x equals twenty nine, and verify by plugging back to confirm the original equation.
Eliminate the denominator in rational exponents by raising both sides to the corresponding power. Then take the appropriate root to solve for x.
Master substitution techniques to solve higher-degree equations by letting u = x^2, factor x^4 − 13x^2 + 36, and compare with faster direct factoring using difference of squares.
In college algebra, factor the equation with negative exponents and rewrite x^-1 as 1/x. Solve each factor equal to zero to find x = -3/2 and x = -1.
Isolate the absolute value and drop it to form plus or minus cases, solving |x|=3, |x-1|=3 (x=4 or x=-2), and |x-8|=7 (x=15 or x=1).
Solve absolute value equations by dropping the absolute values to form two linear equations, x - 4 = 7x + 12 and x - 4 = -(7x + 12), yielding x = -8/3 and x = -1.
Master solving absolute value inequalities by using the |x|<a and |x|>a rules, converting to intervals, and recognizing unions for greater-than cases.
Solve an absolute value inequality by interpreting |x-4| as distance from 4, show that -3 < x-4 < 3, then add 4 to get 1 < x < 7.
Divide both sides by three to get |x+4| less than three, interpret the absolute value as distance from zero, and conclude that x lies between -7 and -1.
This is a complete college level course in Algebra, hence the name College Algebra:)
Basically just,
1) Watch the videos, and try to follow along with a pencil and paper, take notes!
2) Eventually you should be able to do the problems before I do them. Try! Keep watching until you can do the problems on your own:)
3) There are assignments throughout the course. Work through these if you need more practice.
4) Repeat!
If you finish even 50% of this course you will know A LOT of College Algebra and more importantly your Algebra skills will improve a ton!
College Algebra is an awesome class because it prepares you for higher level math in a big way. To be honest, lots of higher level math like Calculus isn't even that hard, it's the ALGEBRA that makes Calculus hard! This means if you become really good at Algebra then once you get to Calculus it will be much easier!
I hope you enjoy watching these videos and working through these problems as much as I have:)
Note this course has lots of very short videos with assignments. If you are trying to learn algebra then this format can be good because you don't have to spend tons of time on the course every day. Even if you can only spend time doing 1 video a day, that is honestly better than not doing any mathematics. You can learn a lot and because there are so many videos you could do 1 video a day. Good luck and I hope you learn a lot of math.