
Explore the theory of integration by defining antiderivatives, such as x^2 and x^2+c; learn indefinite integration, the constant of integration, and integral notation.
Master the basic integration rules: integrate zero to a constant, constants as kx + c, apply the power rule for x^n (n ≠ -1), and use linearity to handle sums.
Explore core trig integration formulas, including ∫ cos x dx = sin x + C and ∫ sin x dx = -cos x + C, with checks by differentiation.
Apply the power rule to integrate x to the minus four, rewrite as -1/3 x to the minus three, include +C, yielding -1/3 x to the minus three.
Learn to integrate a linear combination of cosine and sine by reversing differentiation, yielding 3 sin x minus 8 cos x plus the constant of integration.
Learn to integrate without u-substitution by rewriting sqrt(5x) as sqrt(5) sqrt(x), pull out constants, apply the power rule to x^(-1/2), and obtain 2 sqrt(x)/sqrt(5) + C.
Evaluate the definite integral by rewriting the integrand to powers of x and applying the power rule to x^2 and x^-2, yielding x^3/3 - (1/16)(1/x) + C.
Master the integral of sec^2 x by recognizing it as the derivative of tan x, yielding tan x plus a constant.
Apply the power rule to integrate terms with exponents, raise each exponent by one, multiply by the reciprocal, and obtain the final result 2/3 x^(3/2) + 1/4 x^(1/2) + C.
Learn the power rule for integration by adding one to the exponents and dividing by the new exponent, include the constant of integration, and verify by differentiating.
Apply the power rule to integrate one over the square root of x, rewriting as x^(1/2) and obtaining 2 sqrt(x) + C.
Break the integral into t^(1/2) minus t^(5/2); apply the power rule to obtain (2/3) t^(3/2) minus (2/7) t^(7/2) plus C.
Learn to apply the power rule for integration by adding one to the exponent and dividing by the new exponent, with a note on the negative one exception.
Master integration by breaking the function into simpler powers, applying the power rule, and using reciprocals to divide by the new exponent, with a final plus C.
Learn the power rule for integration: add one to the exponent, divide by it, use the reciprocal for easier division, include the constant of integration, and verify with differentiation.
Expand the product using foil to turn (x+2)(x-3) into x^2 - x - 6. Then apply the power rule to integrate each term and add the constant of integration.
Learn to integrate sine x by recognizing that the derivative of negative cosine x is sine x, yielding negative cosine x plus a constant, verified by differentiation.
Practice integrating a trig expression by matching derivatives to antiderivatives. Use cosine's negative derivative, keep constants, and verify your result by differentiating to check.
Expand the product (x+1)(3x-2), then apply the power rule to integrate the resulting polynomial, yielding x^3 + x^2/2 - 2x + C.
Think backwards when integrating trig functions: identify a function whose derivative matches the integrand, using tangent relationships as clues to quickly find the antiderivative.
Explore integrating expressions, apply the power rule, and note that the derivative of tangent is second squared, so integrating second squared yields tangent plus C, though not the final answer.
Use 1 minus cos squared x equals sin squared x to rewrite cos x over sin^2 x as cot x csc x, giving -csc x + C.
Apply the identity sin two x equals two sin x cos x to simplify the integrand. Integrate to obtain two sin x plus C.
Master indefinite integrals using u-substitution with u = x^2 + 17, align coefficients to match the integral, and apply the power rule to obtain the antiderivative plus a constant.
Use u-substitution with u = x^2 - 12x + 2; du = (2x - 12) dx; integrate to sqrt(u) + C, giving sqrt(x^2 - 12x + 2) + C.
Use a u-substitution with u = sin(3x) to transform the integral; apply the chain rule and divide by 3, yielding the result (1/3) tan(sin(3x)) + C.
Use a u-substitution with u = 17 + 1/x; since du = -1/x^2 dx, rewrite the integral as -∫u^6 du and obtain -u^7/7 + C, then back-substitute.
Solve an integral by substitution, setting u = 3 + cos x, applying the power rule, and obtaining the antiderivative with a constant of integration.
Apply u-substitution with u = tan x to integrate the cube root of tan x times sec^2 x, yielding (3/4) tan^{4/3} x + C.
Use u-substitution to evaluate the indefinite integral of x^2 sin(x^3), substitute u=x^3, obtain -(1/3) cos(x^3) + C, and verify by differentiation.
learn to use u-substitution to integrate sin(2x), pull out constants, and obtain the antiderivative -(1/2) cos(2x) + C, with clear substitution steps.
Apply u-substitution with u equals x plus 2, rewrite x minus 5 as u minus 7, and use power rule to obtain the antiderivative in terms of x plus 2.
Use substitution with u = tan(4x) to handle the square root, pull out constants, and obtain the integral (1/6) [tan(4x)]^(3/2) + C.
learn to integrate the indeterminate integral (2x+1)/sqrt(x+4) using u-substitution, solve for x in terms of u, and obtain (4/3)(x+4)^{3/2} - 14(x+4)^{1/2} + C.
Multiply by the conjugate to apply the difference of squares, rewriting 1/(cos x − 1) as (cos x + 1)/(cos^2 x − 1); then integrate using cotangent and cosecant squared.
Multiply by (1+sin x)/(1+sin x) to apply the difference of squares, rewrite the integrand as sec^2 x plus tan x sec x, and obtain tan x + sec x.
Demonstrates solving 1/(1−cos x) by multiplying by (1+cos x)/(1+cos x), applying difference of squares to obtain (1+cos x)/sin^2 x, then rewriting with familiar trig functions.
Use u-substitution with u = tan x to turn the integral into a power of u, then integrate to obtain one-half tan squared x plus C.
Use u-substitution with u = 1 + 1/x, derive du = -1/x^2 dx, transform the integral to ∫ u^4 du, then back-substitute to get -(1/5)(1 + 1/x)^5 + C.
Use a u-substitution with u equals x cubed plus seven, convert du to 3x^2 dx, rewrite the integrand as u^(-1/2), and obtain 6 sqrt(u) plus 7x^3 plus 7 plus C.
Practice integrating a power function by substitution: set u = 2 − 3x, divide by −3, and apply the power rule to obtain −(2−3x)^{11}/33 + C.
Learn to integrate cosine of 2x using a u-substitution: set u = 2x, factor out 1/2, and obtain (1/2) sin(2x) + C.
Solve an indefinite integral using u-substitution with u = 1/x, rewrite as x^-1, apply the power rule, transform to the integral of sine u du, and obtain cos(1/x) + C.
Learn common integration formulas, including ∫1/x dx = ln|x| + C, apply u-substitution for expressions like 2−x, and explore tan, cot, and sec integrals.
Use u-substitution with u = 5 - 6x to integrate 1/(5-6x) dx. Pull out the constant and obtain the result -1/6 ln|5-6x| + C.
Apply substitution with u = ln x to convert the integral of ln(x^3)/x into ∫u^3 du, then use the power rule to obtain (ln x)^4/4 + C.
Apply u-substitution to integrate the given function, choosing u = 6 + x^(1/3) and transforming the differential to reveal a logarithmic antiderivative.
Example 4 shows using u-substitution with u = 2x, extracting a 1/2 factor, applying a negative natural log of absolute value plus a tangent term, then back-substituting to x.
The lecture demonstrates integrating x over three using a u-substitution, applying the secant integral formula ln|sec x + tan x|, and obtaining 3 ln|sec(x/3) + tan(x/3)| + C.
Apply u-substitution by letting u be the bottom piece; use du as the derivative and recognize the derivative of sine is cosine, convert the integral to ln|u|+C, then substitute back.
Master substitution to integrate five times the cosine of x^2. Let u = x^2, adjust coefficients, and obtain (5/2) sin(x^2) + C.
Use u-substitution with u = cos x to rewrite the integral, manage the negative sign via du = -sin x dx, then integrate cos u and include the constant C.
Apply u-substitution by setting u = 1 − x^2 and use the power rule to integrate x sqrt(1 − x^2), yielding -(1/3)(1 − x^2)^{3/2} + C.
Solve an indefinite integral by substituting u = cot(3x) and using the chain rule, then apply the power rule to integrate a square root, yielding a cot(3x) expression plus C.
Use substitution with u = x^2 - 1 to transform the integral x^3 sqrt(x^2 - 1) dx. Apply the power rule to obtain the final expression.
Use a u-substitution with u = cos x to integrate sin x times cosine of cosine x, giving -sin(cos x) + C.
Use u-substitution with u = x − 1 to transform the integral, then apply the power rule to obtain (2/3)(x − 1)^(3/2) + 2√(x − 1) + C.
Apply a u-substitution with u=3x and pull out 1/3 to use the secant antiderivative ln|sec u + tan u|, yielding (1/3) ln|sec(3x) + tan(3x)| + C.
Apply u-substitution to integrate three times Kosygin squared of seven x squared, yielding an antiderivative -3/14 cot(7x^2) + C.
Learn to integrate e^(3x-6) using a u-substitution, setting u = 3x - 6 and pulling out a 1/3 factor. Conclude with (1/3) e^(3x-6) + C and recover the original variable.
Use a u-substitution with inside piece 2 - x to integrate e^x times sqrt(2 - x), rewrite the root as u^(1/2), apply the power rule, and include C.
Break up the two-term numerator over the single-term denominator and apply exponent rules to subtract exponents when dividing. Use the shortcut of dividing by the coefficient to integrate exponentials.
Apply u-substitution to integrate e^{b x} with respect to x, pulling out constants to get (1/b) e^{b x} + C, as shown by the example of e^{2x} divided by 2.
Use substitution to evaluate an indefinite integral involving e^{x^3}. Derive du from 3x^2 dx, divide by three, substitute, integrate in u, then back-substitute to x and include constant of integration.
Use a u-substitution with u = x − b to transform the integral into a ln|u| + C, showing partial fractions are unnecessary after cancellation.
Rewrite the integral to reveal e^x in the numerator, then substitute u = e^x + 1 to transform the integral into du/u and obtain 2013 ln|e^x+1| + C.
Learn to evaluate the integral ∫ x/(1+e^x) dx by a clever algebraic trick and a u-substitution: set u = 1+e^x, yielding the antiderivative x − ln|1+e^x| + C.
Explore integrating x over 1+ e^x dx using algebraic tricks, split into two integrals, and apply u-substitution u=1+ e^x to obtain a log form with plus C.
this example solves the integral of x e^{x^2} by letting u = x^2 and du = 2x dx, yielding 1/2 e^{x^2} + C.
Apply substitution u = 1 + cot x to transform the integral, then obtain -ln|u| + C with u = 1 + cot x.
Apply a u-substitution with u = 1 + sec theta to evaluate the indefinite integral of sec theta tan theta over 1 + sec theta, yielding ln|u| + C.
Apply a u-substitution with u = ln x to convert the integral into ∫ sin u du, and obtain -cos(ln x) + C.
In this example, evaluate the indefinite integral sin^2 x over 1+cos^2 x by applying chain rule and recognizing the du/u form to obtain a negative natural log of 1+cos^2 x.
Learn to integrate cot x by substitution u = sin x, since cot x = cos x over sin x, yielding the natural log of |sin x| plus C.
Use synthetic division to divide x^4 by x-1, obtaining quotient x^3+x^2+x+1 and remainder 1, then integrate to x^4/4 + x^3/3 + x^2/2 + x + ln|x-1| + c.
Apply a substitution with u = cos x and du = -sin x dx to integrate e^{cos x} sin x dx, yielding -e^{cos x} + C.
Substitute u = x + B; the integral becomes (1/A) ∫ 1/u du = (1/A) ln|u| + C, yielding (1/A) ln|x + B| + C.
Apply u-substitution with u = x - e^(-x) to simplify the integral of (x + e^(-x))/(x - e^(-x)) dx, then obtain ln|u| + C.
Use u-substitution with u = ln x to transform the integral of sqrt(u) du, apply the power rule, and obtain (2/3)(ln x)^(3/2) + C.
Learn key exponential and logarithmic formulas, including d/dx(a^x)=a^x ln a, d/dx(log_a x)=1/(x ln a), and ∫a^x dx=a^x/ln a + C, with change-of-base ideas.
Apply the power rule to integrate x^8 and use the exponential rule for 5^{-x}. Rewrite 5^{-x} as 1/5^x and obtain x^9/9 + 5^{-x}/ln(1/5) + C.
Use a u-substitution with u = sin x to integrate 8^{sin x} cos x dx. Result equals 8^{sin x}/ln 8 + C after substituting back.
Apply u-substitution to integrate 2^{sin x} cos x with respect to x. Let u = sin x, then integrate 2^u du to obtain 2^{sin x}/ln 2 + C.
Apply u-substitution with u = 3x to handle the cosine term and the inside derivative, yielding a 1/3 factor. Integrate 2^u and divide by the natural log of 2.
Rewrite 2^t * 5^t as 10^t using exponent rules, then integrate 2^t and 10^t with ∫ a^x dx = a^x/ln a, yielding 2^t/ln2 + 10^t/ln10 + C.
Learn essential integration formulas for 1/√(a^2−x^2) and 1/(a^2+x^2), with memorized arcsin and arctan forms. Apply substitutions and simple examples to see these patterns.
Apply the standard formula for integrals of 1/(a^2+x^2) to obtain arctan(x/a), and verify by noting the derivative of arctan is 1/(1+x^2).
Use the standard arcsin formula with a=1 to evaluate the integral 1/sqrt(1 - x^2). Recognize that the derivative of arcsin is 1/sqrt(1 - x^2) and apply it to confirm the result.
learn to recognize the standard integral form 1/(a^2+x^2), rewrite the integrand to fit the formula, and apply the arctan result (1/a) arctan(x/a) + c.
Split the integral into two parts, apply a u-substitution for the first and arcsin for the second, yielding -sqrt(1 - x^2) + 3 arcsin(x) + c.
Apply u substitution and arc sine to evaluate an indefinite integral, rewriting x+5 as (x-4)+9 to isolate a term, and then integrate the resulting expressions.
Rewrite the integral to match the arcsin formula, substitute u = 5t^2, pull out 1/2, and obtain (1/2) arcsin(5t^2) + C.
Learn to split an indefinite integral into an ln term and an arctan term using a u-substitution with x plus two, yielding (1/2) ln((x+2)^2+16) - (3/2) arctan((x+2)/4) + c.
Tackles an indefinite integral by recognizing an arctan form, applying the substitution u = e^{2x}, and deriving the antiderivative (1/18) arctan(e^{2x}/9) + C.
Rewrite the integral as an arctan form, substitute u = T^2, pull out constants, and apply the arctan formula to obtain (1/6) arctan(T^2/3) + C.
Let u equal the natural log of x and rewrite the integral. Apply the arc sine formula to arrive at ln(x)/4 + C.
This is literally the ULTIMATE Course on Integration!!
The most important requirement is that you know what a derivative is. If you know that then you can jump into this course as it starts from the very basics of integration.
Basically just,
1) Watch the videos, and try to follow along with a pencil and paper, take notes!
2) Try to do the problems before I do them(if you can!)
3) Repeat!
Integration is an absolutely beautiful subject. I hope you enjoy watching these videos and working through these problems as much as I have:)
Note this course has lots of very short videos. If you are trying to learn math then this format can be good because you don't have to spend tons of time on the course every day. Even if you can only spend time doing 1 video a day, that is honestly better than not doing any mathematics. You can learn a lot and because there are so many videos you could do 1 video a day for a very long time. Remember that math can be challenging and time consuming, so if you just do a little bit every day it can make your journey much more enjoyable. I hope you enjoy this course and learn lots of mathematics.