
Explore the theory of integration by defining antiderivatives, such as x^2 and x^2+c; learn indefinite integration, the constant of integration, and integral notation.
Master the basic integration rules: integrate zero to a constant, constants as kx + c, apply the power rule for x^n (n ≠ -1), and use linearity to handle sums.
Learn to integrate without u-substitution by rewriting sqrt(5x) as sqrt(5) sqrt(x), pull out constants, apply the power rule to x^(-1/2), and obtain 2 sqrt(x)/sqrt(5) + C.
Master the integral of sec^2 x by recognizing it as the derivative of tan x, yielding tan x plus a constant.
Apply the power rule to integrate terms with exponents, raise each exponent by one, multiply by the reciprocal, and obtain the final result 2/3 x^(3/2) + 1/4 x^(1/2) + C.
Expand the product using foil to turn (x+2)(x-3) into x^2 - x - 6. Then apply the power rule to integrate each term and add the constant of integration.
Learn to integrate sine x by recognizing that the derivative of negative cosine x is sine x, yielding negative cosine x plus a constant, verified by differentiation.
Practice integrating a trig expression by matching derivatives to antiderivatives. Use cosine's negative derivative, keep constants, and verify your result by differentiating to check.
Think backwards when integrating trig functions: identify a function whose derivative matches the integrand, using tangent relationships as clues to quickly find the antiderivative.
Use 1 minus cos squared x equals sin squared x to rewrite cos x over sin^2 x as cot x csc x, giving -csc x + C.
Apply the identity sin two x equals two sin x cos x to simplify the integrand. Integrate to obtain two sin x plus C.
Use u-substitution with u = x^2 - 12x + 2; du = (2x - 12) dx; integrate to sqrt(u) + C, giving sqrt(x^2 - 12x + 2) + C.
Use a u-substitution with u = sin(3x) to transform the integral; apply the chain rule and divide by 3, yielding the result (1/3) tan(sin(3x)) + C.
Solve an integral by substitution, setting u = 3 + cos x, applying the power rule, and obtaining the antiderivative with a constant of integration.
Apply u-substitution with u = tan x to integrate the cube root of tan x times sec^2 x, yielding (3/4) tan^{4/3} x + C.
Use u-substitution to evaluate the indefinite integral of x^2 sin(x^3), substitute u=x^3, obtain -(1/3) cos(x^3) + C, and verify by differentiation.
learn to use u-substitution to integrate sin(2x), pull out constants, and obtain the antiderivative -(1/2) cos(2x) + C, with clear substitution steps.
Apply u-substitution with u equals x plus 2, rewrite x minus 5 as u minus 7, and use power rule to obtain the antiderivative in terms of x plus 2.
learn to integrate the indeterminate integral (2x+1)/sqrt(x+4) using u-substitution, solve for x in terms of u, and obtain (4/3)(x+4)^{3/2} - 14(x+4)^{1/2} + C.
Use a u-substitution with u equals x cubed plus seven, convert du to 3x^2 dx, rewrite the integrand as u^(-1/2), and obtain 6 sqrt(u) plus 7x^3 plus 7 plus C.
Practice integrating a power function by substitution: set u = 2 − 3x, divide by −3, and apply the power rule to obtain −(2−3x)^{11}/33 + C.
Learn to integrate cosine of 2x using a u-substitution: set u = 2x, factor out 1/2, and obtain (1/2) sin(2x) + C.
Learn common integration formulas, including ∫1/x dx = ln|x| + C, apply u-substitution for expressions like 2−x, and explore tan, cot, and sec integrals.
Use u-substitution with u = 5 - 6x to integrate 1/(5-6x) dx. Pull out the constant and obtain the result -1/6 ln|5-6x| + C.
Apply u-substitution to integrate the given function, choosing u = 6 + x^(1/3) and transforming the differential to reveal a logarithmic antiderivative.
Example 4 shows using u-substitution with u = 2x, extracting a 1/2 factor, applying a negative natural log of absolute value plus a tangent term, then back-substituting to x.
Apply u-substitution by letting u be the bottom piece; use du as the derivative and recognize the derivative of sine is cosine, convert the integral to ln|u|+C, then substitute back.
Master substitution to integrate five times the cosine of x^2. Let u = x^2, adjust coefficients, and obtain (5/2) sin(x^2) + C.
Use u-substitution with u = cos x to rewrite the integral, manage the negative sign via du = -sin x dx, then integrate cos u and include the constant C.
Apply u-substitution by setting u = 1 − x^2 and use the power rule to integrate x sqrt(1 − x^2), yielding -(1/3)(1 − x^2)^{3/2} + C.
Use substitution with u = x^2 - 1 to transform the integral x^3 sqrt(x^2 - 1) dx. Apply the power rule to obtain the final expression.
Use u-substitution with u = x − 1 to transform the integral, then apply the power rule to obtain (2/3)(x − 1)^(3/2) + 2√(x − 1) + C.
Apply a u-substitution with u=3x and pull out 1/3 to use the secant antiderivative ln|sec u + tan u|, yielding (1/3) ln|sec(3x) + tan(3x)| + C.
Use a u-substitution with inside piece 2 - x to integrate e^x times sqrt(2 - x), rewrite the root as u^(1/2), apply the power rule, and include C.
Use substitution to evaluate an indefinite integral involving e^{x^3}. Derive du from 3x^2 dx, divide by three, substitute, integrate in u, then back-substitute to x and include constant of integration.
Learn to evaluate the integral ∫ x/(1+e^x) dx by a clever algebraic trick and a u-substitution: set u = 1+e^x, yielding the antiderivative x − ln|1+e^x| + C.
Apply a u-substitution with u = 1 + sec theta to evaluate the indefinite integral of sec theta tan theta over 1 + sec theta, yielding ln|u| + C.
Apply a u-substitution with u = ln x to convert the integral into ∫ sin u du, and obtain -cos(ln x) + C.
Substitute u = x + B; the integral becomes (1/A) ∫ 1/u du = (1/A) ln|u| + C, yielding (1/A) ln|x + B| + C.
Apply u-substitution with u = x - e^(-x) to simplify the integral of (x + e^(-x))/(x - e^(-x)) dx, then obtain ln|u| + C.
Use u-substitution with u = ln x to transform the integral of sqrt(u) du, apply the power rule, and obtain (2/3)(ln x)^(3/2) + C.
Apply the power rule to integrate x^8 and use the exponential rule for 5^{-x}. Rewrite 5^{-x} as 1/5^x and obtain x^9/9 + 5^{-x}/ln(1/5) + C.
Use a u-substitution with u = sin x to integrate 8^{sin x} cos x dx. Result equals 8^{sin x}/ln 8 + C after substituting back.
Apply u-substitution to integrate 2^{sin x} cos x with respect to x. Let u = sin x, then integrate 2^u du to obtain 2^{sin x}/ln 2 + C.
Apply u-substitution with u = 3x to handle the cosine term and the inside derivative, yielding a 1/3 factor. Integrate 2^u and divide by the natural log of 2.
Apply the standard formula for integrals of 1/(a^2+x^2) to obtain arctan(x/a), and verify by noting the derivative of arctan is 1/(1+x^2).
Use the standard arcsin formula with a=1 to evaluate the integral 1/sqrt(1 - x^2). Recognize that the derivative of arcsin is 1/sqrt(1 - x^2) and apply it to confirm the result.
Apply u substitution and arc sine to evaluate an indefinite integral, rewriting x+5 as (x-4)+9 to isolate a term, and then integrate the resulting expressions.
Tackles an indefinite integral by recognizing an arctan form, applying the substitution u = e^{2x}, and deriving the antiderivative (1/18) arctan(e^{2x}/9) + C.
Rewrite the integral as an arctan form, substitute u = T^2, pull out constants, and apply the arctan formula to obtain (1/6) arctan(T^2/3) + C.
This is literally the ULTIMATE Course on Integration!!
The most important requirement is that you know what a derivative is. If you know that then you can jump into this course as it starts from the very basics of integration.
Basically just,
1) Watch the videos, and try to follow along with a pencil and paper, take notes!
2) Try to do the problems before I do them(if you can!)
3) Repeat!
Integration is an absolutely beautiful subject. I hope you enjoy watching these videos and working through these problems as much as I have:)
Note this course has lots of very short videos. If you are trying to learn math then this format can be good because you don't have to spend tons of time on the course every day. Even if you can only spend time doing 1 video a day, that is honestly better than not doing any mathematics. You can learn a lot and because there are so many videos you could do 1 video a day for a very long time. Remember that math can be challenging and time consuming, so if you just do a little bit every day it can make your journey much more enjoyable. I hope you enjoy this course and learn lots of mathematics.