
Compute vectors from initial and terminal points by subtracting coordinates to obtain u and v, then confirm equivalence when magnitudes and directions match.
Apply the unit vector formula by multiplying vector V by 1 over its magnitude, here √65, to get (4/√65, 7/√65). Verify the result by its magnitude, which equals one.
Find a vector with a given magnitude in the same direction as a reference vector by forming its unit vector and scaling by the target magnitude; example yields (0,4).
Compute the dot product of two space vectors by multiplying corresponding coordinates and summing the results, illustrated with vectors [1, 2, 4] and [-3, -2, 0], yielding -7.
Compute the angle between space vectors using the dot product, confirming orthogonality when u·v = 0 and theta = pi/2 (90 degrees) through component form and the cosine formula.
Derive direction angles and direction cosines for a vector in 3-D, normalize it, express V in unit-vector components, and verify cos^2 alpha plus cos^2 beta plus cos^2 gamma equals 1.
Find the direction angles of the vector from components (5, 9, 7) by computing magnitude sqrt(155) and the cosines 5/sqrt(155), 9/sqrt(155), 7/sqrt(155), then determine alpha, beta, gamma in degrees.
Compute the cross product of two vectors by expanding the determinant with i, j, k and 2x2 minors.
Compute the cross product of two vectors using a determinant, express the result in component form, and verify the resulting vector is perpendicular to both originals.
Learn to calculate the distance between two points in space using the 3d distance formula, with a step-by-step example that yields the result sqrt(6).
derive a line in space from a point and a parallel vector; obtain parametric form x1 + a t, y1 + b t, z1 + c t, and symmetric form.
Derive the plane equation from a point on the plane and a normal vector, using n · (x - x1, y - y1, z - z1) = 0.
Learn to find the equation of a plane through a point with a given normal vector using the form (x−x0)A+(y−y0)B+(z−z0)C=0, resulting in y=5 for the example.
Find the equation of a plane from a point and a normal vector using the standard form a(x−x1)+b(y−y1)+c(z−z1)=0, with the normal components a,b,c and the point (x1,y1,z1).
This Calculus 3 Course has hundreds of videos:)
Note: If you know some Calculus 1 you could probably jump in and complete a significant portion of this course without Calculus 2.
Basically just,
1) Watch the videos, and try to follow along with a pencil and paper, take notes!
2) Try to do the problems before I do them(if you can!)
3) Repeat!
Calculus 3 is an absolutely beautiful subject. I hope you enjoy watching these videos and working through these problems as much as I have:)
Note this course has lots of very short videos. If you are trying to learn math then this format can be good because you don't have to spend tons of time on the course every day. Even if you can only spend time doing 1 video a day, that is honestly better than not doing any mathematics. You can learn a lot and because there are so many videos you could do 1 video a day for a very long time. Remember that math can be challenging and time consuming, so if you just do a little bit every day it can make your journey much more enjoyable. I hope you enjoy this course and learn lots of mathematics.