Algebra -Learn complete concepts of Algebra 1 & Algebra 2

Name: Algebra -Learn complete concepts of Algebra 1 & Algebra 2
Rating: 4.4 (43 reviews)

A course on Algebra that boosts your confidence and helps you solving Algebra & math exam problems with an ease.

Created bySandeep Kumar Mathur

Last updated 5/2026

English

What you'll learn

Learn basic concepts, Formulae, Important results and tips and tricks of Algebra from basics to advanced
Acquire a solid foundation in Algebra 1 & Algebra 2 concepts that will be useful in further studies in mathematics, science, and engineering.
Learn to identify and use mathematical properties,
Acquire the skills necessary to manipulate and simplifying algebraic expressions
Learn to solve mathematical problems using algebraic techniques and methods.
Develop an understanding of algebraic concepts and operations, including linear equations, polynomials, quadratics etc..

Course content

17 sections • 472 lectures • 37h 20m total length

Number System16:08
Properties of Numbers31:07
Q.no.11:29
Q.no.20:47
Q.no.30:36
Q.no.42:07
Q.no.51:32
Q.no.62:39
Laws of Indices16:15
Q.no.11:37
Q.no.22:53
Q.no.31:47
The lecture demonstrates simplifying an expression by rewriting x^{-1}, y^{-1}, z^{-1} as reciprocals, combining terms with the common denominator x y, y z, z x, and selecting option B.
Q.no.44:07
Q.no.51:57
Learn to simplify a product of square roots and cube roots using fractional exponents in algebra. The expression reduces to the square root of P, confirming option a.
Q.no.61:38
Q.no.73:10
Q.no.85:11
Standard Form of Notations6:13
Explore standard form of notation, or scientific notation, where numbers between 1 and 10 are multiplied by integral powers of ten. Convert values like 2.9 and 0.29 by shifting decimal.
Rationalization16:09
Q.no.14:05
Q.no.25:59
Q.no.36:16
Apply cross multiplication and squaring to remove radical for x = sqrt(3) + 1, rewrite x^2 and x^3, substitute into x^3 + 2x^2 - 8x + 7, and get 10.
Q.no.43:24
Rationalize the denominator to find 1/x for x = 3 + sqrt(8), then use (x + 1/x)^2 = x^2 + 1/x^2 + 2 to obtain x^2 + 1/x^2 = 34.
Quiz

Factorisation Basics15:19
Q.no. 12:46
Learn to factor expressions using grouping, identify common factors, and form binomial factors through guided examples.
Q.no. 22:45
Q.no. 31:35
Q.no. 41:26
Q.no. 53:15
Q.no. 1(Formulae Based)2:42
Q.no. 2(Formulae Based)6:12
Q.no. 3(Formulae Based)2:43
Q.no. 4(Formulae Based)2:20
Factorisation of Quadratic Trinomials6:09
Q.no. 15:22
Q.no. 22:44
Q.no. 33:27
Some more formulae for factorisation2:08
Q.no. 12:45
Q.no. 26:12
Q.no. 34:09
Q.no. 42:34
Q.no.53:24
Formula for Expression a^3+b^3+c^3-3abc6:42
Explore the formula for the expression a^3+b^3+c^3-3abc and apply it to simplify with a+b+c, including a notable special case when a+b+c equals zero.
Q.no. 13:42
Q.no. 23:59
Q.no. 31:55
Q.no. 45:24
Q.no.53:01
Q.no.62:56
Q.no.73:16
Q.no.85:31
Q.no.93:16
Q.no.102:50
Remainder Theorem and Factor Theorem7:15
Q.no.16:11
Learn to factor a quadratic by testing possible x values from factors of 12 to identify zeros and express the polynomial as a product.
Q.no.23:49
test whether x-1 is a factor of the given expression, divide by x-1 to obtain the quotient x^2+4x+4, and factor the result as (x-1)(x+2)^2 to illustrate complete factorization.
Q.no.35:28
Q.no.41:51
Q.no.510:00
Q.no.68:18
Q.no.72:55
Quiz
Practice Sheet1:09

Basic Concepts pf Polynomials13:51
Relation between zeros and the coefficients of a quadratic polynomial6:02
Q.no. 15:06
Q.no. 23:04
Q.no. 31:48
Q.no. 43:01
Q.no. 51:52
Q.no. 64:28
Q.no. 74:38
Division Algorithm of Polynomials3:43
Q.no. 1(Division Algorithm)4:47
Q.no. 24:54
Q.no.32:33
Q.no.42:47
Q.no.53:13
Q.no.64:57
Q.no.73:42
Q.no.82:21
Basic Concepts of Cubic Polynomials9:00
Q.no. 1(Cubic Polynomials)11:16
Q.no. 22:39
Q.no. 36:52
Q.no. 43:39
Quiz
Miscellaneous Questions0:22
Q.no. 14:10
Q.no. 24:59
Q.no. 33:52
Q.no. 45:01
Q.no. 52:44
Quiz

Basic Concepts : Linear Equations in one variable12:26
Q.no. 1(Linear Equations in one variable)3:36
Q.no. 21:17
Q.no. 31:48
Q.no. 42:06
Q.no. 51:21
Q.no. 62:49
Q.no. 1(Word Problems of Linear Equations in one Variable)1:54
solve a word problem with linear equations in one variable: two natural numbers whose sum is 31; set x and 31−x, so x+(31−x)=31, giving 15 and 16.
Q.no. 20:59
Q.no. 31:26
Q.no. 46:28
Q.no. 53:18
Let x be the son's age and form 6x+4 = 4x+16 to solve an algebra age problem where the father is six times the son now and four times later.
Q.no. 62:48
Q.no. 73:47
Q.no. 82:18
Q.no. 92:18
Practice solving a 40 percent passing threshold in algebra, using a linear equation to find x, with the example concluding x equals 500.
Q.no. 103:22
Basic Concepts : Linear Equations in two variable5:58
Explore linear equations with two variables, learn how to find the solution pairs (x, y) for systems of equations and their graph, and distinguish between consistent and inconsistent cases.
Consistent and inconsistent system of linear equations2:46
Explore the difference between consistent and inconsistent systems of linear equations with two unknowns, identifying scenarios with at least one solution versus no solution.
Q.no. 11:56
Q.no. 23:07
Methods of solving linear equations in two variables1:41
Graphical Method of solving linear equations in two variables17:57
Method of Substitution6:01
Q.no.16:01
Q.no.24:41
Method of Elimination4:52
Q.no. 1 Elimination Method3:54
Method of Cross Multiplication7:03
Q.no.13:55
Q.no.22:21
Q.no.34:04
Show how a pair of linear equations in standard form yields infinitely many solutions when corresponding coefficients satisfy specific equalities derived from comparing the equations.
Conditions for solvability of system of linear equations9:08
Q.no.13:07
Q.no.22:02
Q.no. 1(Application of Linear equations in two variables in word Problems )5:33
Q.no. 26:50
this lecture shows how to translate a word problem into a two-variable equation system with x and y, use elimination or substitution to solve, and determine x=13 and y=1.5.
Q.no. 33:52
Q.no. 44:10
Q.no. 57:50
Q.no.66:46
Q.no.79:17
Solving Equations by Vedic Mathematics Methods : Basic Equations8:00
Solving Equations by Vedic Maths Methods : Shunyam Samay Samuchaye10:47
Some Typical Examples6:35
Quiz

Introduction : Basic Concepts11:00
Finding out of roots of a Quadratic Equation14:21
Nature of the roots of Quadratic Equations6:49
Relation between the roots of a Quadratic Equation7:03
Formation of a Quadratic Equation4:10
Q.no.1(Objective Questions)2:29
Q.no. 21:08
Q.no. 33:09
Q.no. 42:51
Q.no. 51:48
Q.no. 62:40
Q.no. 73:14
Q.no. 82:23
Q.no. 94:26
Q.no. 103:51
Q.no. 113:34
Explore how to analyze a quadratic equation involving x^2 using the discriminant to determine imaginary roots. The calculation yields a negative discriminant, so the equation has no real solutions.
Q.no.123:09
Q.no.134:24
Using that sine alpha and cosine alpha are roots of ax^2+bx+c=0, apply the sum and product of roots and sin^2 alpha+cos^2 alpha=1 to derive b^2 = a^2+2ac.
Q.no.141:53
Q.no.151:51
Q.no. 1(i)(ii) (Short Answer Questions)3:08
Q.no. 1(iii)(iv)1:49
Compute the discriminant of the quadratic equation to determine the root nature. A zero discriminant yields equal roots, while a positive discriminant yields two distinct roots.
Q.no. 1(v)(vi)3:14
Q.no. 1(vii)(viii)2:35
Analyze a quadratic equation by evaluating the discriminant, revealing cases with two distinct real roots, and, after simplification, showing the resulting equation has no real solutions.
Q.no. 1(ix)(x)2:41
Q.no. 2(i)(ii)2:55
Q.no. 2(iii)(iv)2:20
Q.no. 2(v)(vi)6:24
Q.no. 34:08
Q.no. 43:36
Explore when a quadratic equation with rational coefficients has irrational roots, using the quadratic formula and a worked example showing the discriminant 129 yields irrational roots (3 ± sqrt(129))/4.
Q.no. 55:55
Q.no. 62:06
Q.no. 72:38
Q.no. 1(Some more problems)1:48
Analyze the quadratic equation (x-1)^2 + 2(x+1) = 0, simplify to standard form, and compute the discriminant. Conclude the discriminant is negative, so the equation has imaginary solutions.
Q.no. 24:22
Q.no. 1(Solving a Quadratic Equation)2:30
Q.no. 24:12
Q.no. 36:42
Q.no. 1(i)(ii) (Some more problems)4:29
Master solving quadratic equations in algebra 1 and 2 by applying the quadratic formula, identifying coefficients a, b, c, and computing roots through example problems.
Q.no.1(iii)(Iv)3:47
Solve quadratic equations by applying the quadratic formula to find the roots, using coefficients a, b, and c. The lesson walks through evaluating expressions and deriving multiple roots.
Q.no. 1(v)(vi)4:09
Q.no. 1(vii)1:52
Apply algebraic simplification to a quadratic expression composed of x^2 minus 11 and x plus 1, solving for related values and verifying the equation.
Q.no. 2(i)(ii)6:05
Q.no. 2(iii)(iv)7:23
Q.no. 2(v)2:16
Transform the quadratic x^2 - 2x + 1 into (x-1)^2, factor into two factors, set each to zero, and find x = 1.
Q.no.1(Long Answer Questions)7:32
Q.no. 24:58
Q.no. 39:56
Q.no. 44:54
Conduct algebraic reasoning to solve a two-step age problem by formulating and factoring a quadratic, revealing Ziba's current age as 14 years.
Q.no. 58:45
Q.no. 65:04
Q.no. 74:34
Q.no.84:37
Q.no.98:12
Q.no.105:41
Q.no.1118:15
Q.no.1211:12
Q.no.135:09
Q.no.1(i) & (ii)(Some More Questions)6:07
Q.no.1(iii) & (iv)6:38
Q.no. 1(v)4:11
This lecture demonstrates solving a quadratic equation using the quadratic formula, explains discriminant evaluation (b^2 - 4ac) to determine real or imaginary roots, and shows computing the roots.
Q.no. 25:10
Q.no. 33:38
Q.no.42:29
Q.no.54:51
Derive alpha and beta as cube roots of unity from x^2 + x + 1 = 0 using the quadratic formula, then evaluate alpha^19 and beta^7.
Quiz

Introduction9:50
Q.no. 16:14
Practice solving exponent and square expressions, including negative exponents and division steps, to see how power rules simplify complex questions into one or other simple values.
Q.no. 23:56
Q.no. 33:10
Q.no. 44:24
Q.no. 51:45
Q.no.61:14
Q.no.72:19
Basic operations in complex numbers14:59
Cojugate of a Complex Number and its properties8:25
Modulus of a complex number and its properties5:07
Representation of a complex Number18:32
Q.no. 17:24
Q.no. 23:53
Q.no. 33:03
Q.no. 43:49
Q.no. 52:39
Q.no. 65:48
Q.no. 72:34
Q.no. 84:04
Q.no. 95:33
Q.no. 105:23
Cube Roots of Unity8:50
learn the cube roots of unity and factor z^3-1 into (z-1)(z^2+z+1), identifying the real root 1 and the complex roots omega and omega squared, with omega^2+omega+1=0.
Q.no.11:54
Analyze a first algebra question with omega and omega squared, applying ω^2 = 1 and 1 + ω + ω^2 = 0 to prove the product equals four.
Q.no.21:44
Q.no.31:37
Q.no.43:36
The lecture solves the cube root of unity problem by simplifying omega to the fourth and eighth powers, using omega^3=1 and 1+omega+omega^2=0 to show the expression equals nine, option d.
Q.no.54:13
Q.no.63:03
Quiz

Basic Concepts : Sequence and series8:07
Explore basic concepts of sequence and series in algebra, including arithmetic progressions, common difference, first term, and how to represent and analyze term sequences and series.
General term or n th term of an AP4:52
Q.no. 12:15
Q.no. 21:57
Analyze the sequence, determine its difference, and apply the plus one method to derive terms such as four and nine, illustrating independence of end terms in the pattern.
Q.no. 32:14
Q.no. 43:46
Q.no. 51:18
Q.no. 64:19
Explore logarithms and exponent laws to simplify expressions, using the log difference, log of a fraction, and the power minus one concept demonstrated in Q.no. 6.
Q.no. 72:43
Q.no. 82:30
Q.no. 93:42
Identify an arithmetic sequence with first term 3 and difference 4, and use a_n = a + (n-1)d to test whether 184 belongs; it does not.
Q.no. 104:45
Q.no. 116:11
Q.no. 124:22
Q.no. 135:02
Q.no. 144:32
Q.no. 155:01
Q.no. 167:35
Q.no. 177:37
Selection of terms of an AP3:40
Q.no. 1(Selection of terms in an A.P.)4:23
Q.no. 26:07
Q.no. 34:09
Q.no.46:06
Sum to n terms of an AP7:03
Q.no. 1 (Sum of n terms of an AP)2:09
Q.no. 22:15
Q.no. 33:09
Q.no. 42:32
Q.no. 55:24
Sum all three-digit numbers divisible by seven using an arithmetic series. From 105 to 994 with a common difference of 7 and 128 terms, total 70,336.
Q.no. 63:15
Q.no. 74:24
Q.no. 83:55
Explore arithmetic progression problems in algebra by using the end terms, the sum, and the first term to find A and B via the AP formulas.
Q.no. 93:53
Q.no. 106:36
Q.no.116:14
The lecture solves for the nth term in an arithmetic progression with first term 1 and difference 5, using sum and term formulas to find X = 36.
Q.no.124:38
Q.no.136:26
Derive the common difference in an arithmetic progression from L, a, and k, eliminate a, L, and n, and show that k equals 2s.
Properties of Arithmetic Progrssions16:11
Q.no. 1(Properties of Arithmetic Progressions)1:54
Q.no. 22:48
The lecture demonstrates how three terms can form an arithmetic progression and shows that multiplying each term by ABC preserves the AP.
Q.no. 33:32
Q.no. 47:58
Q.no. 54:00
Q.no. 66:16
Insertion of Arithmetic Means9:43
Explore how to insert automatic means between two numbers, derive the common difference, and compute the sum of the inserted arithmetic means.
Q.no. 1 Arithmetic Mean1:18
Q.no. 2 Arithmetic Mean2:56
Q.no. 34:43
Q.no. 42:08
quiz

Basic Concepts of GP7:27
Q.no. 12:06
Delve into exponents and fractions by reducing powers in denominators, and determine generators, as shown by manipulating expressions like a^7, a^6, and a^{-1} on the board.
Q.no. 23:37
Q.no. 32:57
Q.no. 42:37
Problem Sheet
Selection of terms of a GP2:37
Q.no. 1(Selection of terms of a G.P.)7:42
Sum to n terms of a GP5:32
Q.no. 1(Sum of n terms of a G.P.)1:38
Q.no. 25:23
explore a geometric progression and derive the sum formula for a finite series, using terms with powers of five and the ratio r to compute the total.
Q.no. 38:45
Q.no. 43:41
Q.no. 53:33
Q.no. 67:14
Sum of an infinite GP2:42
Q.no. 11:47
Q.no. 22:52
Q.no. 34:00
Q.no. 41:56
Q.no. 51:36
Q.no. 64:39
Q.no. 98:41
Q.no. 81:29
Q.no. 74:28
Q.no. 101:11
Explore infinity formulas and core algebraic expressions, solving and simplifying equations such as six over six and one minus r to uncover equalities.
Q.no. 113:30
Q.no. 128:41
derive values for the first term E and common ratio R by solving four equations, using elimination and the sum to infinity formula with 57 for a geometric progression.
Q.no. 134:42
Solve a geometric progression problem where the first term and common ratio yield a sum of 40, using algebra to determine the terms.
Q.no. 144:35
Q.no. 152:11
Q.no. 166:24
Analyze a ball dropped from 120 meters, bouncing to one fifth of its height, and compute the total distance traveled as it rises and falls until rest.
Q.no. 173:58
Q.no. 186:22
Properties of GP15:55
Q.no. 14:11
Q.no. 23:24
Q.no. 33:10
This lecture demonstrates log properties for powers and squares, showing how log of a power can be expanded and simplified using standard log rules.
Insetion of Geometric means between two given numbers11:57
Explore the method to obtain the geometric mean between two numbers via the common ratio in a geometric progression, using the formula.
Some important properties of AM and GM between two numbers11:20
This lecture covers key properties of the arithmetic mean and geometric mean for two numbers, including how GM lies between them when the numbers are positive.
Q.no. 14:45
Q.no. 26:57
Q.no. 34:58
Solve a positive-number algebra problem by using A plus B and A minus B relationships to find A equals 16 and B equals 4.
Q.no. 43:37
Q.no. 54:36
Quiz
Practice Sheet-12:54
Practice Sheet-21:07
Complete practice sheet-2 to apply concepts from algebra 1 and algebra 2. Sharpen your problem-solving skills with targeted algebra exercises.

Requirements

You will understand solution of selected and excellent questions step by step on each topic of Algebra

Description

If you find it difficult to remember various formulas of Algebra ? If you have a feeling of not being confident in Algebra ? If you facing difficulty in solving Algebra questions and feel that you need to strengthen your basics? Then you have come to the right place.

Algebra is an important branch of Mathematics. It helps in solving many problems arise in practical situations. Generally many questions do come from this topic in competition exams. The course is useful for both beginners as well as for advanced level. Here, this course covers the following areas in details:

Factorisation
Polynomials
Linear Equations
Quadratic Equations
Inequations
Complex Numbers
Principle of Mathematical Induction
Sequence and Series(Arithmetic Progressions (A.P.))
Geometric Progressions (G.P.)
Some Special Series
Harmonic Progressions (H.P.)
Exponential Series
Permutations and Combinations
Binomial Theorem
Logarithms
Set Theory
Each of the topic has a great explanation of concepts and excellent and selected examples.

I am sure that this course will be create a strong platform for students and those who are planning for appearing in competitive tests and studying higher Mathematics.

You will also get a good support in Q&A section . It is also planned that based on your feed back, new topics like relation and function etc. will be added to the course. Hope the course will develop better understanding and boost the self confidence of the students.

Waiting for you inside the course!

Who this course is for:

Students who are studying Algebra in their academic syllabus and wishes to learn it
Students preparing for IIT JEE,NDA,MCA entrance exams.

Algebra -Learn complete concepts of Algebra 1 & Algebra 2

What you'll learn

Explore related topics

Course content

Preliminary23 lectures • 2hr 17min

Factorisation40 lectures • 2hr 49min

Polynomials29 lectures • 2hr 11min

Linear Equations45 lectures • 3hr 34min

Quadratic Equations65 lectures • 5hr 11min

Inequations13 lectures • 58min

Complex Numbers29 lectures • 2hr 29min

Principle of Mathematical Induction4 lectures • 25min

Arithmetic Progressions (A.P.)50 lectures • 3hr 53min

Geometric Progressions (G.P.)47 lectures • 3hr 39min

Requirements

Description

Who this course is for: